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[자바스크립트] [팝업창] 이미지 클릭시 html문서없이 큰이미지로 새창띄우기

<html>
<head>
<title>..</title>
<meta http-equiv="Content-Type" content="text/html; charset=euc-kr">
<script language="JavaScript">
var win1Open = null
function displayImage(picName, windowName,
windowWidth, windowHeight){
return window.open(picName,windowName,"toolbar=no,

scrollbars=no,resizable=no,width=" + (parseInt(windowWidth)+20) + ",height=" + (parseInt(windowHeight)+15))
} function winClose(){
if(win1Open != null) win1Open.close()
} function doNothing(){}
</script> <script language="JavaScript1.1">
function displayImage(picName, windowName,

windowWidth, windowHeight){
var winHandle = window.open("" ,windowName,"toolbar=no,scrollbars=no,

resizable=no,width=" + windowWidth + ",height=" + windowHeight)
if(winHandle != null){
var htmlString = "<html><head><title>Picture</title></head>"
htmlString += "<body leftmargin=0 topmargin=0 marginwidth=0 marginheight=0>"
htmlString += "<a href=javascript:window.close()><img src=" + picName + " border=0
alt=닫기></a>"
htmlString += "</body></html>"
winHandle.document.open()
winHandle.document.write(htmlString)
winHandle.document.close()
}
if(winHandle != null) winHandle.focus()
return winHandle
}
</script>
</head>
<body>
<a href="javascript:doNothing()"
onClick="win1Open=displayImage('큰 이미지파일', 'popWin1', '300', '400')" onMouseOver="window.status='Click to display picture'; return true;" onMouseOut="window.status=''">
<img src=이미지파일" border="0"></a>
</body>
</html>


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